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From: | Doug Stewart |
Subject: | Re: [Axiom-developer] please check your Schaums |
Date: | Mon, 28 Apr 2008 07:10:17 -0400 |
User-agent: | Thunderbird 2.0.0.12 (X11/20080227) |
address@hidden wrote:
My schaums is the same as your Schaums but it is old (not as old as yours) I have a New Schaums at work But I will not Be in to work today :-)In 14.661 Schaums claims: integral acoth(x/a) = x*acoth(x)+a/2*log(x^2-a^2) ^^^^^^^^ Axiom claims integral acoth(x/a) = x*acoth(x/a)+a/2*log(x^2-a^2) ^^^^^^^^^^ Is this a Schaums typo? Tim _______________________________________________ Axiom-developer mailing list address@hidden http://lists.nongnu.org/mailman/listinfo/axiom-developer
My Maxima agrees with Axium. integrate(acoth(x/a),x); (%o8) (a*log(x^2/a^2-1))/2+x*acoth(x/a)
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