Re: [ft] Why is FT_F26Dot6 defined as a signed long

[Lawrence D'Oliveiro]

On Thu, 14 Feb 2019 11:58:09 -0800, Wink Saville wrote:

> Interesting, but on a 32bit platform, with long == 32 bits, that
> wouldn't work.

There is this thing called “LP64” versus “LLP64”, for describing code
generation on 64-bit architectures. GCC (and I think all the other
compilers that work on Linux) is “LP64”, which means that “long” and
pointers are both 64 bits. On Windows, it seems “LLP64” is the norm,
where “long” is 32 bits and you need to say “long long” to get 64 bits.

C99 introduced the stdint.h include file, which gives explicit names to
you can use to request particular sizes of integers, to avoid this
discrepancy.