[Help-bash] About printf "%d\n" with no arguments.

[Peng Yu]

Hi,

The following command will print "0". But I think the appropriate
output should be nothing. As mentioned in the man page "Write  the
formatted  arguments  to the standard output under the control of the
format", since there are no arguments, nothing should be printed. Is
there a way to configure printf to do what I just described? Thanks.

~$ printf "%d\n"
0

-- 
Regards,
Peng

P.S. man page also says "If the format requires more arguments than
are supplied, the extra format specifications behave as if a zero
value or null str had been supplied.  The return value is zero on
success, non-zero on failure." But I don't think this default is
appropriate in all cases.