Re: [Help-bash] use variable as array name

[phillip]

Thanks a lot!

Phillip

On 4 January 2015 03:14:04 CET, "Eduardo A. Bustamante López" <address@hidden> 
wrote:
>On Fri, Jan 02, 2015 at 08:15:08PM +0100, Phillip Sz wrote:
>> Hi,
>> 
>> I want to use a variable as an array name, but I dont see a way to do
>> this. For example:
>> 
>> namelength="$((address@hidden -1))"
>> 
>> and now I want to replace "array" with for example $1.
>
>That's possible with namerefs:
>
>| address@hidden ~ % bash script
>| 2
>| address@hidden ~ % cat script
>| #!/bin/bash
>| 
>| thearray=(foo bar baz)
>| 
>| set -- thearray
>| typeset -n key="$1"
>| 
>| namelength="$((address@hidden -1))"
>| echo "$namelength"
>
>Or you could do it with indirection, by creating a copy of the array.
>Something
>like:
>
>key="address@hidden" copy=("${!key}") address@hidden
>echo "$length"