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From: | Alasdair McAndrew |
Subject: | Re: [Axiom-mail] A pattern matching question |
Date: | Sat, 2 Jun 2007 07:44:54 +1000 |
--try this in an input file
tt:=operator 'tt
ttrules := rule
tt(n^(a | integer?(a))) == t/a
tt(n/(n-1)) == 1/t
tt(n/(n^a+(X | integer?(a) and (n-1)^a = n^a +X))) == 1/t^a
ttrules tt(n^6)
ttrules tt(n/(n-1))
ttrules tt(n/(n-1)^2)
ttrules tt(n/(n-1)^30)
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