[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Locate Element Matching Search Pattern in Array Variable
From: |
Hon-Chi Ng |
Subject: |
Locate Element Matching Search Pattern in Array Variable |
Date: |
Tue, 24 Jul 2001 14:12:35 -0700 |
Hi
I hope this is the right place to ask questions about bash usage, as
the name suggesting bug report. I apologize if this is not the proper
place to do so, and please kindly direct me to the right place. BTW,
is the news:gnu.bash.bug Usenet same as bug-bash@gnu.org?
I'm looking for Bash syntax/construct that can locate an element (the
first matching) in an array variable for a given search pattern.
Basically, the array variable and search pattern are given, and either
the subscript or the element is expected if found, or either -1 or
null if not found. For illustration, it will be something similar to
lsearch in Tcl & grep in Perl.
Before I go off and write a function with for loop to do so, I'm
interested in a more efficient and concise way in achieving it.
For example, I can find out if at least an element matching the search
pattern exists in a given array variable by using [[ == ]] construct
as shown below, without defining a function to loop thru the array
variable.
E.g. True if element not prefixed with - exists in foo[]
if [[ " ${foo[*]} " == *" "!(-*)" "* ]]; then ...; else ...; fi
However, I don't know how to get the element (or its subscript) that
matches the search pattern, without writing an elaborate function.
Thanks. I appreciate your help.
Regards
Hon-Chi
------------------------------------------------------------
--== Sent via Deja.com ==--
http://www.deja.com/
[Prev in Thread] |
Current Thread |
[Next in Thread] |
- Locate Element Matching Search Pattern in Array Variable,
Hon-Chi Ng <=