man page "-c" explanation clarity

[Paul A. Clarke]

Configuration Information [Automatically generated, do not change]:
Machine: i386
OS: linux-gnu
Compiler: i386-redhat-linux-gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i386' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i386-redhat-linux-gnu' 
-DCONF_VENDOR='redhat' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
-DHAVE_CONFIG_H  -I.  -I. -I./include -I./lib  -D_LARGEFILE_SOURCE 
-D_FILE_OFFSET_BITS=64 -O2 -g -pipe -m32 -march=i386 -mtune=pentium4
uname output: Linux pc.austin.ibm.com 2.6.9-34.EL #1 Fri Feb 24 16:44:51 EST 
2006 i686 i686 i386 GNU/Linux
Machine Type: i386-redhat-linux-gnu

Bash Version: 3.0
Patch Level: 15
Release Status: release

Description:
The man page states, for the "-c" option:
       -c string If the -c option is present, then  commands  are  read  from
                 string.   If  there are arguments after the string, they are
                 assigned to the positional parameters, starting with $0.
I think the phrase "arguments after the string" is confusing in that the 
"arguments" here are really still within "the string", not after.

Repeat-By:
$ man bash

Fix:
I'd suggest slightly different wording, such as:
"... If argments follow the respective commands within the string, they are..."

--
Regards,
Paul Clarke