Re: Segmentation fault

[Chet Ramey]

seba wrote:
> GNU bash, version 3.2.25(1)-release (i686-pc-linux-gnu)
> Copyright (C) 2005 Free Software Foundation, Inc.
> 
> #!/bin/sh
> 
> fib() {
>        n=$1
>        [ $n == 0 -o $n == 1 ] && return $n
>        fib $(($n-1))
>        ret1=$?
>        fib $(($n-2))
>        ret2=$?
>        return $(($ret1 + $ret2))
> }
> 
> for ((i=0;$i<36;i++))
> do
>        fib $i
>        echo "n=$i=>$?"
> done

You managed to write yourself an infinitely-recursive function, and
eventually ran out of stack space.  `==' is a string operator, not a
numeric operator, when used with `['.

Chet
-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                       Live Strong.  No day but today.
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/