Re: Inconsistent behaviour of +=() and existing array keys

[helmut . karlowski]

> On Fri, Nov 28, 2014 at 03:47:49PM -0500, Maarten Billemont wrote:
> least for the associative arrays case, because in the case of normal  
> arrays,
> ksh93 does some pretty funny things:
>
> | dualbus@hp ~ % ksh93 -c 'a=(); a+=([0]=b); typeset -p a'
> | typeset -A a=([0]=b) # Ha! Now 'a' is an associative array...

Associative is more "default" in ksh93 as in bash:

a=([0]=4)
typeset -p a

gives in bash:
declare -a a='([0]="4")'

in ksh93:
typeset -A a=([0]=4)

An empty array (a=()) gives in ksh93:
typeset -C a=()

-C means Compound variable, which is something different.

-Helmut

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