Re: BUG??

[PePa]

Of course... My own stupidity.

It did raise the question for me, what would be the recommended way to
'group' expressions, where other languages would use brackets, like:

if (((q==1)) || [[ $r ]]) && grep -q $s $file
then
  echo "$s is in $file, and either q is 1 or r is not empty"
fi

I guess this works, but it spawns a subshell. Is there a better way?

Thanks,
Peter


On 29/12/2559 08:38, Chet Ramey wrote:
> On 12/28/16 8:09 PM, Peter & Kelly Passchier wrote:
>> Is this a bug? These both output "q=1"
>>
>> q=1
>> [[ ((q==1)) ]] && echo q=1
>>
>> q=0
>> [[ ((q==1)) ]] && echo q=1
>>
> 
> No. These both end up checking whether the length of the string "q==1" is
> non-zero, which it is.
>