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Re: expr '0' pattern capture issue.
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From: |
Andreas Schwab |
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Subject: |
Re: expr '0' pattern capture issue. |
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Date: |
Mon, 08 Dec 2003 15:01:23 +0100 |
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User-agent: |
Gnus/5.1002 (Gnus v5.10.2) Emacs/21.3.50 (gnu/linux) |
benjamin gerard <address@hidden> writes:
> $expr 'a0b' : 'a\(.\)b' \| '1
>
> The previous sample returns '1'. I assume this is because the matching
> pattern is '0' and it is evaluate as false.
>
> I am just wandering if this is expected behaviour ?
You have just answered you question above.
expr1 | expr2 Returns the evaluation of expr1 if it is neither null nor
zero; otherwise, returns the evaluation of expr2 if it is
not null; otherwise, zero.
Andreas.
--
Andreas Schwab, SuSE Labs, address@hidden
SuSE Linux AG, Maxfeldstraße 5, 90409 Nürnberg, Germany
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