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bug#20928: cut (v. 8.21), using -f option with a single column
From: |
Pádraig Brady |
Subject: |
bug#20928: cut (v. 8.21), using -f option with a single column |
Date: |
Mon, 29 Jun 2015 16:31:00 +0100 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:31.0) Gecko/20100101 Thunderbird/31.6.0 |
tag 20928 notabug
close 20928
stop
On 29/06/15 09:18, Kuchta, Tomasz wrote:
> Hello.
>
> I’m not sure if this is a bug - I just wanted to let you know.
> Thanks,
> Tomek
>
> ——
>
> When there is more than one column and we go beyond the number of columns
> with the -f option, the output is empty
>
> $ echo "test1 test2" | cut -d' ' -f1
> test1
> $ echo "test1 test2" | cut -d' ' -f2
> test2
> $ echo "test1 test2" | cut -d' ' -f3
>
> $
>
> ——
>
> When there is only one column and we go beyond 1 with the -f option, the
> output remains the first column
>
> $ echo "test1" | cut -d' ' -f1
> test1
> $ echo "test1" | cut -d' ' -f2
> test1
> $ echo "test1" | cut -d' ' -f3
> test1
That difference in behavior is there for compat reasons.
To induce the behavior you expect, you need the -s option.
thanks,
Pádraig.
- bug#20928: cut (v. 8.21), using -f option with a single column, Kuchta, Tomasz, 2015/06/29
- bug#20928: cut (v. 8.21), using -f option with a single column,
Pádraig Brady <=
- bug#20928: cut (v. 8.21), using -f option with a single column, Kuchta, Tomasz, 2015/06/30