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bug#22155: Wrong char count with UTF8 in sort -k


From: Holger Klene
Subject: bug#22155: Wrong char count with UTF8 in sort -k
Date: Sat, 12 Dec 2015 23:53:40 +0100
User-agent: KMail/4.14.6 (Linux/3.19.0-39-generic; KDE/4.14.6; x86_64; ; )

Hello!

 

Given a text-file "sort.but.txt" with find-output like this:

07. Feb 2015 15:57 ./mess.jpg

05. Mär 2015 13:30 ./mess.jpg

 

Basically two columns: a date and a filename

I want sort to discard the duplicate lines for the same file using -u to keep only the first and -k to skip over the date column

 

> sort sort.bug.txt -u -s -k 1.20 --debug

sort: es werden die Sortierregeln für »de_DE.UTF-8“ verwendet

sort: führende Leerzeichen sind signifikant in Schlüssel 1: Sie sollten daher

wahrscheinlich auch „b“ angeben

05. Mär 2015 13:30 ./mess.jpg

___________

07. Feb 2015 15:57 ./mess.jpg

__________

 

As the underlines in debug mode show, the keys start position depends on whether the month name contains pure ASCII or the German Umlaut ä.

 

There's a hint coming up, to apply option -b as this one character offset could possibly be overcome thanks to the separating whitespace between the columns.

 

> sort sort.bug.txt -u -s -k 1.20 -b --debug

sort: es werden die Sortierregeln für »de_DE.UTF-8“ verwendet

05. Mär 2015 13:30 ./mess.jpg

__________

07. Feb 2015 15:57 ./mess.jpg

__________

 

In fact, it does correct the underlines, but still -u gives both lines, though I want it to discard the second line. You can add more lines for the same file, but sort insists on keeping exactly two: one with Umlaut and the other without.

 

This is: sort (GNU coreutils) 8.23

 

Thanks for the great utilities.

Holger

 

--

|_|/ MfG

| |\ Holger Klene

 

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