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bug#23922: cut fails for non-delimited input lines with -f 2
From: |
Assaf Gordon |
Subject: |
bug#23922: cut fails for non-delimited input lines with -f 2 |
Date: |
Fri, 8 Jul 2016 23:20:10 -0400 |
tag 23922 notabug
close 23922
stop
Hello Jens,
> On Jul 8, 2016, at 19:05, Jens Mueller <address@hidden> wrote:
>
> $ echo "abc" | cut -f 2 -d " "
>
> and I expect the empty line as output but you get "abc\n".
It is not a bug, but correct behavior (though perhaps unexpected) to print
"abc" in this case.
The POSIX standard says (at
http://pubs.opengroup.org/onlinepubs/9699919799/utilities/cut.html):
"-s
Suppress lines with no delimiter characters, when used with the -f option.
Unless specified, lines with no delimiters shall be passed through untouched."
In GNU cut's help screen (cut --help) shows:
-s, --only-delimited do not print lines not containing delimiters
The following will demonstrate:
$ printf "abc\nd f\n" | cut -f2 -d " "
abc
f
$ printf "abc\nd f\n" | cut -s -f2 -d " "
f
As such, I'm closing this bug report - but discussion can continue by replying
to this thread.
regards,
- assaf