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Re: Possible bug in array handling after end of input (END handler)
From: |
Andrew J. Schorr |
Subject: |
Re: Possible bug in array handling after end of input (END handler) |
Date: |
Fri, 4 Dec 2020 14:10:34 -0500 |
User-agent: |
Mutt/1.5.21 (2010-09-15) |
Hi,
On Fri, Dec 04, 2020 at 03:28:54PM +0100, Christian Schmidt wrote:
> function dump() {
> for (i in vars) printf ("%s:%s ", i, vars[i]);
> print;
> delete vars;
> }
Why are you calling "print" after dumping the contents of the vars
array? It prints out $0. You are getting confused by that.
If you modify the function like so, the problem should become obvious
to you:
function dump() {
for (i in vars) printf ("%s:%s ", i, vars[i])
printf "\n"
print "And I'm also printing $0 here for some unknown reason"
print
delete vars
}
Also, FYI, you don't need those semicolons at the end of each line.
A semicolon is needed only to separate two statements that are on
the same line (and not separated by a linefeed).
Regards,
Andy