/*

Illustration of incorrect behavior for %.{precision}s when the corresponding
arg is an illegal multibyte sequence in the current locale.  ANSI/ISO C99
 states

  If no l length modifier is present, the argument shall be a pointer to the
  initial element of an array of character type. {237: No special provisions
  are made for multibyte characters.}  Characters from the array are written
  up to (but not including) the terminating null character. If the precision
  is specified, no more than that many bytes are written.



$ diff -u glibc uClibc 
--- glibc	2003-08-13 18:04:38.000000000 -0500
+++ uClibc	2003-08-13 18:04:30.000000000 -0500
@@ -1,4 +1,5 @@
 locale: en_US.UTF-8
 n=3  buf="??????"
 n=15  buf="  ??????"
-n=18  buf="n=-1  Invalid or incomplete multibyte or wide character
+n=18  buf="??????"
+n=16  Success


*/


#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <locale.h>

int main(void)
{
	const char *s;
	int n;
	unsigned char illegal_utf8[] = "\x80\x80\x80";
	char buf[128];

	if (!(s = setlocale(LC_ALL, "en_US.UTF-8"))) {
		printf("setlocale failed!\n");
		return EXIT_FAILURE;
	}
	printf("locale: %s\n", s);

	memset(buf, 'x', 10);
	buf[10] = 0;
	n = snprintf(buf, sizeof(buf), "%s", illegal_utf8);
	n = printf("n=%d  buf=\"%s\"\n", n, buf);
	n = printf("n=%d  buf=\"%5s\"\n", n, buf);
	n = printf("n=%d  buf=\"%.5s\"\n", n, buf);
	fflush(stdout);
	fprintf(stderr, "n=%d  %m\n", n);

	return EXIT_SUCCESS;
}