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bug#67862: 30.0.50; Handler-bind and ert-test-error-debug
From: |
Stefan Monnier |
Subject: |
bug#67862: 30.0.50; Handler-bind and ert-test-error-debug |
Date: |
Tue, 26 Dec 2023 11:25:22 -0500 |
User-agent: |
Gnus/5.13 (Gnus v5.13) |
>> (ert-deftest ert-test-error-debug ()
>> (let ((test (make-ert-test :body (lambda () (error "Error message")))))
>> (condition-case condition
>> (progn
>> (let ((ert-debug-on-error t))
>> (ert-run-test test))
>> (cl-assert nil))
>> ((error)
>> (cl-assert (equal condition '(error "Error message")) t)))))
>>
>> Until now, this test passes just like that, i.e. without entering
>> the debugger. With the new code, this test does enter the debugger.
>>
>> Can anyone give me a hand figuring out why/how the debugger is not entered
>> with the current code?
>
> Could that be from the condition-case that the test puts around the
> ert-run-test? Like in
>
> (condition-case var
> (let ((debug-on-error t))
> (error "error"))
> (error "no debugger"))
>
OK, so now I understand how that test succeeds, but instead I don't
understand why it is expected to succeed or more specifically what it is
intended to test.
AFAICT
(let ((ert-debug-on-error t))
(ert-run-test test))
is supposed to say "run the test and please pop up a debugger if there's
an error". The ERT code even goes to the trouble to store&use the value of
`ert-debug-on-error` upon entry to the tests rather the value that
happens to be current when the error is signaled.
So to me the code looks like it wants to test that `ert-debug-on-error`
indeed brings up a debugger, tho none of the surrounding code tries to
detect whether the debugger is/was entered, and instead that surrounding
code uses `condition-case` which prevents entering the debugger.
Is it really the purpose of this test to make sure that "even if we ask
for the debugger, `condition-case` prevents the use of a debugger"?
Stefan