Re: grep 2.5.1: two errors in 'make check'

[Patrick Smith]

Stepan Kasal wrote:
> >         echo - | grep -E -e '(*)b'
>
> This is a change in the way regex interprets this illegal pattern.
> New regex correctly reports the error:

Perhaps the test case should be changed to accept either 1 or 2 as the 
exit code?

> >         echo civic | grep -E -e \
> >            '^(.?)(.?)(.?)(.?)(.?)(.?)(.?)(.?)(.?).?\9\8\7\6\5\4\3\2\1$'
> >
> > expecting exit code 0.  Instead, the exit code is 1, with no output.
>
> This seems to be a bug in current regex code.

Do the glibc folks know about this?  Or should I report it to them?


> To hide the first problem and solve the second one, ./configure grep
> --with-included-regex .

Thanks.  I'll do this.