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-frepo does not create repository
From: |
Ronald Fischer |
Subject: |
-frepo does not create repository |
Date: |
2 May 2002 01:32:50 -0700 |
I have the following declaration in one file:
template<typename T> extern void f(T);
The function f is called, but the code for f resides in a separate
file. Following the advice in the gcc online documentation, I
compile the file containing the calling site with
-frepo
but the compiler does not create a repository file, and the linker
consequently complains about the missing functions (such as
f<int>(int)).
I use gcc 3.0.2 and ld 2.9.1
Ronald
- -frepo does not create repository,
Ronald Fischer <=
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/02
- Re: -frepo does not create repository, Ronald Fischer, 2002/05/03
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/05
- Re: -frepo does not create repository, Ronald Fischer, 2002/05/06
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/06
- Re: -frepo does not create repository, Ronald Fischer, 2002/05/07
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/07
- Re: -frepo does not create repository, André Pönitz, 2002/05/07
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/08
- Re: -frepo does not create repository, André Pönitz, 2002/05/13