gnash
[Top][All Lists]
Advanced

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: [Gnash] Where does gnash send to trace output to?


From: Meryl Silverburgh
Subject: Re: [Gnash] Where does gnash send to trace output to?
Date: Tue, 6 Mar 2007 01:04:14 -0600

On 3/5/07, strk <address@hidden> wrote:
On Sun, Mar 04, 2007 at 03:15:45PM -0600, ying lcs wrote:

> Regarding your response, i found this in flare output:
>
>  movieClip 130 fullDisplay {
>
>    #initclip
>      Object.registerClass('fullDisplay', logic.Movie);
>    #endinitclip
>  }
>
> and then:
> logic.Movie = v1;
>        logic.Movie extends MovieClip;
>        var v2 = v1.prototype;
>        v2.initController = function () {
>           // ....
>        };
>
>        v2.setMovie = function (_video_id, image_url, movie_url, l,
> _track_id, eurl, append_vars) {
>            // ...
>         };

Ok, next step is checking in which order the logic.Movie definition
and the registerClass call are executed. Expected and obtained order
should be encoded in a testcase.


From the flare outout, it registers 'logic.Movie' in movieClip 130.
And then calling 'player.movie.setMovie' in frame 1.

movieClip 130 fullDisplay {

   #initclip
     Object.registerClass('fullDisplay', logic.Movie);
   #endinitclip
 }

 frame 1 {
   movie = player.movie;
   movie.base_url = '/';
   movie.tracker_cls = logic.PlayerTracker;
   movie.setMovie(video_id, undefined, undefined, l, t);
   movie.playMovie();
  /....
}

But from the swfmill output 'the class logic.Movie' is export after
sprite ID 141 is defined.

<DefineSprite objectID="141" frames="0">
       <tags>
         <End/>
       </tags>
     </DefineSprite>
     <Export>
       <symbols>
         <Symbol objectID="141" name="__Packages.logic.Movie"/>
       </symbols>
     </Export>

But I don't how to find out what is the expected right order of the
logic.Movie definition  and the registerClass call are executed.

what is the relationship between the movieClip # (e.g. 131) and the
sprite object id?


--strk;






reply via email to

[Prev in Thread] Current Thread [Next in Thread]