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From: | Larry Kollar |
Subject: | Re: [Groff] pic problem |
Date: | Tue, 13 Jul 2004 23:19:29 -0400 |
The only way I can account for all of A, B, C, D is that the logic of the loop for n = a to b by c do {...} is: [1] Set n = a. [2] If a > b, break; else execute {...} [3] increment a by c [default 1], and go to [2]. which would presuppose that a <= b to start with, and c > 0. Not the logic one would expect!
Interesting... have I actually uncovered a bug? Using Heinz's suggestion (box wid 1 ht 1 sprintf("%g", 32-n);) worked, so for now I'll assume it's a case of "does it hurt when you do that? then don't do that." -- Larry Kollar k o l l a r @ a l l t e l . n e t Unix Text Processing: "UTP Revival" http://home.alltel.net/kollar/utp/
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