[Help-bash] New conditional evaluation with a regex

[Jesse Molina]

Greetings all

I am trying to remember some goofy/clever way to do something.  Is there 
another way to do this, or any alternate methods which you prefer?

I'm working on test conditional expressions via [].  I was writing a 
script where I needed to evaluate and take action for certain multiple 
exit codes of some program.

Let us say;

TEST1=7



The first way to do this uses single [] brackets and I'll break it up 
for readability;

if [ \
    "$TEST1" == 2 \
    -o "$TEST1" == 3 \
    -o "$TEST1" == 4 \
    -o "$TEST1" == 5 \
    -o "$TEST1" == 6 \
    -o "$TEST1" == 7 \
    ] ; then
        echo YES
else
        echo NO
fi



But this is obviously long and annoying if I have many things to match 
against.  I really just want to match against a regex.

Then, I remembered that you could use =~ to do something like that, but 
I had to google up to remember that you can only do it in double [[]] 
brackets (new style);

if [[ "$TEST1" =~ 2|3|4|5|6|7 ]] ; then
        echo YES
else
        echo NO
fi



However, I seem to remember having done this previously with single 
brackets, in a clever manner that was neat and didn't need as many lines 
or repetitive goop as the first method mentioned above.  Anyone have a 
clue WTF I'm talking about, because I sure don't.

Any other clever ways to do complex conditional tests, or neat tricks on 
the subject?



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