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Re: [Help-bash] How to make variable set in () accessible outside?


From: Greg Wooledge
Subject: Re: [Help-bash] How to make variable set in () accessible outside?
Date: Thu, 3 May 2012 08:15:14 -0400
User-agent: Mutt/1.4.2.3i

On Thu, May 03, 2012 at 06:06:11AM -0500, Peng Yu wrote:
> http://lists.gnu.org/archive/html/help-bash/2012-02/msg00000.html

"This solution and other solutions (including gnu parallel) suffer the
problem of not able to understand bash function."

So, you are *still* trying to create an N-job scheduler that can schedule
bash functions?

And none of the examples in http://mywiki.wooledge.org/ProcessManagement
were helpful?

Is there a particular reason why your scheduler can't schedule a job
that is bash -c 'source /path/to/myfunc; myfunc'?

Have you also rejected the alternative method of exporting the function
through the environment (bash to bash)?  In that case, the job you
schedule would simply be bash -c 'myfunc', with myfunc having been
exported in advance.

Or in other words, "What are you trying to do?"



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