Re: [Help-bash] array indirection

[John Kearney]

Am 05.05.2012 02:20, schrieb Bill Gradwohl:

Can anyone explain why one pass of this loop works and then fails.

If it didn't work at all, or worked all the time I could understand, but working once and then quitting is confusing.

array=(11 12 13 14 15)
variableName='array'

for ((x=0; x<address@hidden; ++x)); do
   echo "array[${x}]=${!variableName[$x]}"
done
==================
Produces:
address@hidden 01.ycc# ./tst pass3
array[0]=11
./tst: line 33: !variableName[$x]: unbound variable


--
Bill Gradwohl

AFAIK this syntax ${!variableName[$x]} isn't supported.

I'm guessing the reason the first one worked is because
${!variableName[0]} is a special case because
${!variableName[0]} is a synonym for ${!variableName}
and ${!variableName} is supported.




 

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