Re: [Help-bash] hi, doubt about xargs

[Greg Wooledge]

On Mon, Jun 03, 2013 at 08:25:30PM +0200, John Kearney wrote:
> As I understand it the default behaviour of find is {} expands to only one
> file name as such
> 
> find .  -name '*.txt' -execdir sh -c 'cp "${0}" "${0%.txt}.bak"' {}
> is the same thing? or what am I missing something.

You are definitely missing something.  You MUST end an -exec with either
a ; or +.  If you use ; then find will fork/exec one sh for every file
that it finds.  If you use + then it will bundle up several filenames
and pass them all at once.

In the example above, you'd need to end with ; because your script is
only written to handle one argument.

(Assuming the nonstandard -execdir has the same syntax as -exec.)

> This on the other hand does make sense.
> 
> find .  -name '*.txt' -print0 | xargs -n10 -p3 sh -c 'for f; do cp "$f"
> "${f%.txt}.bak"; done' _ {}

In this one, there's an xargs with nonstandard options, and the {} is
an argument of xargs rather than find.  I won't even try to guess what
this does.  (On my HP-UX machine, xargs -p is "Prompt mode: The user is
asked whether to execute command prior to each invocation."  I'm guessing
yours is different.)

(It also looks like you forgot a -0 option to your xargs.)