Re: [Help-bash] "local" modifies the behavior of "$?"

[Chet Ramey]

On 6/23/13 11:39 PM, Dan Douglas wrote:

> Not documented but frequently asked.

Not quite.  From the `SIMPLE COMMAND EXPANSION' section of the man page:

"If  there is a command name left after expansion, execution proceeds as
described below.  Otherwise, the command exits.  If one of  the  expan-
sions  contained a command substitution, the exit status of the command
is the exit status of the  last  command  substitution  performed.   If
there were no command substitutions, the command exits with a status of
zero."

Similarly, the descriptions of `local' and `declare' list the conditions
under which they will return non-zero.

Chet

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/