Re: [Help-bash] How pass arguments to a command run by the -c option of bash?

[Greg Wooledge]

On Sun, Jul 21, 2013 at 11:01:45AM -0500, Peng Yu wrote:
> I'm trying to run a command by the -c option. But 'a' is not passed to
> address@hidden Does anybody know what is correct way to pass the command
> arguments to a command run by the -c option of bash?
> 
> ~$ bash -c 'echo x $@' a b c
> x b c

bash -c 'echo x "$@"' _ a b c

You need to put a placeholder in there to become $0.

More realistic example:

find . -type f -name '*.sh' -exec bash -c '
    for f; do mv -i "$f" "${f%.sh}"; done
' _ {} +

Don't use "-" for the placeholder, because some commands interpret that
as a synonym for "--", and then it just vanishes.  Likewise, don't use
"--" either.  Almost anything else is fine.