Re: [Help-bash] subtle "break" strangeness

[Chet Ramey]

On 9/2/13 5:30 PM, Matej Kosik wrote:

> However, when I try:
> 
>       for i in `seq 1 5`;do echo $i; test $i = 3 && (break); done
> 
> then I see:
> 
>       1
>       2
>       3
>       4
>       5
> 
> I guess that "break" need not to be supposed to work inside a subshell.

How can it?  The subshell started to run `break' understands that it is
running in a loop -- it inherits that understanding from its parent --
but there is no way to communicate the `breaking' status from a child
back to its parent.

Chet
-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/