Re: [Help-bash] How to not print command in $() when set -v is enabled?

[Eduardo A . Bustamante López]

On Mon, Feb 10, 2014 at 08:57:38AM -0600, Peng Yu wrote:
> Hi,
> 
> The following example shows that the 2nd echo is also printed. Since
> it is in $(), a better behavior might be not to print it. Is there a
> way to do so in bash? Thanks.
> 
> ~/linux/test/bash/man/builtin/set/-v/$($ cat main.sh
> #!/usr/bin/env bash
> 
> set -v
> echo "$(echo "Hello World!")"
> ~/linux/test/bash/man/builtin/set/-v/$($ ./main.sh
> echo "$(echo "Hello World!")"
> echo "Hello World!")"
> echo "Hello World!")
> echo "Hello World!"
> Hello World!
> 
It's really hard to tell from your example what's part of the command
line and what's not... your prompt is a bit weird.

Though, why would not want it to get printed? The point of -v/-x is
to trace the execution of commands inside a script, and commands
executed in command substitution are still commands that have an
effect on the flow, so... let's keep them in the output :)?

-- 
Eduardo Alan Bustamante López