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Re: [Help-bash] Firefox Parameter

From: Joydeep Chakrabarty
Subject: Re: [Help-bash] Firefox Parameter
Date: Tue, 16 Dec 2014 00:59:19 +0530
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:31.0) Gecko/20100101 Thunderbird/31.3.0

On Monday 15 December 2014 08:38 PM, Greg Wooledge wrote:
On Mon, Dec 15, 2014 at 11:20:39AM +0000, Joydeep Chakrabarty wrote:
contains -

#! /bin/sh
firefox -newtab "$@" || firefox "$@" &

I made it executable with +x option. Now when I run it using "./ff", it always opens up my homepage(google). What am I doing
wrong here?

This isn't so much a Bash question as a Firefox question.  Start with
the basics.  If you type this command at a shell prompt:

firefox -newtab

what does it do?  For me, it opens a new window (not a new tab) with in the URL bar, and Google's front
page displayed.

This means that "firefox -newtab ..." is not the right command.  You
need to find out what the right command IS, before you can put it in
a script.
might be useful, or it might not.  It was my first Google result for
"firefox command line parameters".

Thanks, it worked. I just removed the -newtab option.
I could not figure out to which group I should post. I thought I might be passing wrong parameter to my shell script. So I posted here.

Thanks again.

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