Re: [Help-bash] Printing from Array

[Chris F.A. Johnson]

On Thu, 21 May 2015, Richard Taubo wrote:

> Hei!
>
> Creating a simple array, I am just wondering why the second printf line
> does not print any results from the array at all.
> I was assuming it would print the "two" and "three" lines in the array.
>
> Thanks for feedback!
>
> #!/bin/bash
> MyData="One,two,three"
> declare -i q
> OIFS=$IFS
> IFS=$','
> for myColumn in $MyData; do
>        MyArray[q++]="${myColumn#*}"
>        printf "%s\n" "$q: ${MyArray[q-1]}"
>        printf "%s\n" "$q: ${MyArray[q]}"
> done
> IFS=$OIFS

   Your problem has already been explained, but I would suggest doing
   it differently (assuming that the info is already in a
   comma-delimited variable):

IFS=, read -ra MyArray <<< "$MyData" ## read variable into an array

for (( q = 1; q < address@hidden; q++))
do
  printf "%s\n" "$((q-1)): ${MyArray[q-1]}"
  printf "%s\n" "$q: ${MyArray[q]}"
done

   Or:

for q in "address@hidden"
do
  ((q==0))&&continue
  printf "%s\n" "$((q-1)): ${MyArray[q-1]}"
  printf "%s\n" "$q: ${MyArray[q]}"
done
for q in "address@hidden"
do
  ((q==0))&&continue
  printf "%s\n" "$((q-1)): ${MyArray[q-1]}"
  printf "%s\n" "$q: ${MyArray[q]}"
done

--
Chris F.A. Johnson, <http://cfajohnson.com>