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[Help-bash] command substitution $( ) waits for child’s &
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From: |
Patrick Schleizer |
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Subject: |
[Help-bash] command substitution $( ) waits for child’s & |
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Date: |
Fri, 29 May 2015 23:16:43 +0000 |
Hi!
script x:
#!/bin/bash
set -x
output="$(./y 2>&1)"
script y:
#!/bin/bash
set -x
sleep 3 &
Script x waits until script y exits.
Due to using command substitution $( ). Without $( ) it wouldn't wait.
Why does command substitution ignore the '&'?
Is it possible to prevent waiting?
Cheers,
Patrick
- [Help-bash] command substitution $( ) waits for child’s &,
Patrick Schleizer <=