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Re: [Help-bash] printf -v
From: |
Pierre Gaston |
Subject: |
Re: [Help-bash] printf -v |
Date: |
Sun, 8 May 2016 19:22:21 +0300 |
On Sun, May 8, 2016 at 6:42 PM, Wu Shuangrong <address@hidden> wrote:
> Hello,
> I am trying to save a string with a trailing newline to a variable,
> following is what i did:
> printf -v var1 “%s\n” xyz
> now when i echo $var1 it seems the newline disappears, as echo adds a
> newline to the end of the output, so i expected a blank line appeared on
> the screen, but that’s not what happened. So what’s happening here?
>
> Thanks,
> Shuangrong
>
>
>
> if you don't quote $var1 bash splits the variable on space tab and
newlines (by default, this can be changed) and then remove these.
you should use: echo "$var1", or even better: printf '%s\n' "$var1"