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Re: [Help-bash] Passing script by fd on Linux and setuid scripts
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From: |
Chet Ramey |
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Subject: |
Re: [Help-bash] Passing script by fd on Linux and setuid scripts |
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Date: |
Mon, 1 Aug 2016 21:03:51 -0400 |
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User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.11; rv:45.0) Gecko/20100101 Thunderbird/45.2.0 |
On 8/1/16 8:11 AM, Petr Skočík wrote:
> Hi.
>
> The bash reference mentions that /dev/fd/* files are treated specially,
> as filedescriptors, when used in conditionals.
They're not treated specially on Linux, which provides /dev/fd (or its
close relation, /proc/self/fd) directly. There's no reason for bash to
handle it specially as a filename argument. All that needs to be done
is for the kernel to pass the open file descriptor to bash using the
/dev/fd/N pathname.
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU address@hidden http://cnswww.cns.cwru.edu/~chet/