Re: [Help-bash] Does the parser backtrack?

[Dan Douglas]

On Tue, Oct 18, 2016 at 11:52 AM, Dan Douglas <address@hidden> wrote:
> Needless to say, a reasonable person would write something like this
> instead:
>
> $( (foo <<EOH1) && foo <<EOH2)
> + ( (
> EOH1
> ) ) + 1 +
> EOH2

Oh I guess the ash derivatives are unusual in this particular case.
Most shells want their heredoc delimited within the command
substitution. Oh well, reinforces my point that $(... <<DOC) is so
useless that I never use them like this. I'd normally do:

{ x=$( (cat) && cat <&3); } <<\EOH1 3<<\EOH2
+ ( (
EOH1
) ) + 1 +
EOH2

...multi-line command substitutions are easier this way too.