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Re: [Help-bash] How unnamed pipe is done in bash?
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From: |
Chet Ramey |
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Subject: |
Re: [Help-bash] How unnamed pipe is done in bash? |
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Date: |
Thu, 19 Jan 2017 18:27:58 -0500 |
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User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.12; rv:45.0) Gecko/20100101 Thunderbird/45.6.0 |
On 1/19/17 4:51 PM, Peng Yu wrote:
> Hi, I don't quite understand who unamed pipe is done in bash. It seems
> unnamed pipe is mapped to a fd in /dev/fd/<id>. 63 is always used as
> the first one. Why the 2nd command won't run correctly?
>
> $ cat <(echo xxx)
> xxx
> $ cat $(echo <(echo xxx))
> cat: /dev/fd/63: Bad file descriptor
Think about the parent-child relationship. The process substitution is
valid in the subshell spawned to run the command substitution. The parent
shell doesn't know anything about it.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU address@hidden http://cnswww.cns.cwru.edu/~chet/