Re: [Help-bash] Clarify the meaning of 's' in $- and the meaning of -s when invoking bash

[Stephane Chazelas]

2017-03-16 08:27:53 +0100, address@hidden:
[...]
> It seems to me that the 's' flag is supposed to be shown in $- when
> bash reads  the standard input. Such  a case occur when  bash is invoked
> with the -s option. Example:
> 
>     $ echo 'echo $-' | bash -s
>     hBs
> 
> However,  bash reads  the standard  input also  when there  are no  more
> arguments  after option  processing.  Example
> 
>    $ echo 'echo $-' | bash
>    hB
[...]

That was a non-conformance (or at least deviation from every
other Bourne-like shell) of bash. It was fixed in 4.4

$ echo 'echo $- $BASH_VERSION' | bash
hBs 4.4.11(1)-release

IIRC, that was discussed last year either on the Austin group or
bug-bash mailing list.

-- 
Stephane