Re: string escaping in bash

[Alex fxmbsw7 Ratchev]

you may be looking for
# printf %b "$str"
to interpret the string by prrintf

or mass chained singular statements, like you showed or similiar

On Fri, Mar 12, 2021, 16:05 Peng Yu <pengyu.ut@gmail.com> wrote:

> Hi,
>
> I wondering if there is a simple but robust way to implement string
> escaping.
>
> Specifically, the string "\n" (a slash and the letter "n") should be
> replaced as a newline character, the string "\t" (a slash and the
> letter "t") should be replaced as a tab character, and "\\" (two
> consecutive slashes should be replaced with a single slash. All other
> characters and their preceding slash (if there is) should remain as
> is.
>
> If I use a multi-string-replacement strategy, it will not be robust.
> For example, if I do it in the order 1) \\ -> \, 2) \n -> newline, \\n
> will not be replaced correctly. The result should be "\n" (a slash
> followed by the letter "n").
>
> $ x='\\n'; x=${x//\\\\/\\}; x=${x//\\n/$'\n'}; declare -p x
> declare -- x="
> "
>
> Does anybody have a robust way to implement this in bash?
>
> --
> Regards,
> Peng
>
>