Handling short and long options

[angioberlinguer]

It is a way to handle short and long options manually.  Pelhaps I can simplify 
the "-s"
option.  For the "-s" option, I wanted to accept wildcards (e.g. A*) which the 
shell would
expand.

Noticed a small mistake in the last part, which should be

 (*) fls+=( "$2" ) ; shift 1 ;;
esac



‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
On Monday, September 6, 2021 11:05 PM, Dennis Williamson 
<dennistwilliamson@gmail.com> wrote:

> On Mon, Sep 6, 2021, 5:40 PM angioberlinguer via help-bash@gnu.org wrote:
>
> > I have made the following function to parse short and long options.
> > Perhaps I do not need to
> > call `set -- $*`.
> > The while loop could also be changed. I want to allow splitting on space
> > and equal sign
> > so I can call it with `-s val` and `--src=val`.
> > rando ()
> > {
> > local incl=() fls=()
> > IFSPREV="$IFS" # Save IFS (splits arguments on whitespace by default)
> > IFS=" =" # Split arguments on " " and "="
> > set -- $* # Set positional parameters to command line arguments
> > IFS="$IFSPREV" # Set original IFS
> > local iarg=0 narg="$#"
> > while (( narg > 0 )); do
> > opt="$1"
> > iarg=$(( iarg + 1 ))
> > case $opt in
> > ("--incl") incl+=("$2") ; shift 2 ;;
> > ("-s"|"--src"|"--source") src=$( "$2" ) ; shift 2 ;;
> > ("-d"|"--dst"|"--destin") dst="$2" ; shift 2 ;;
> > ("--") shift 1 ; break ;;
> > ("-") printf '%s\n' "Unknown option: $1" ; shift 1 ;;
> > () fls+=( "$2" ) ; shift 1 ;;esac
> > done
>
> WTH is going on?