Re: code not working ..

[alex xmb sw ratchev]

On Wed, Sep 11, 2024, 1:35 AM alex xmb sw ratchev <fxmbsw7@gmail.com> wrote:

>
>
> On Wed, Sep 11, 2024, 1:14 AM Greg Wooledge <greg@wooledge.org> wrote:
>
>> On Wed, Sep 11, 2024 at 00:25:15 +0200, alex xmb sw ratchev wrote:
>> > i got in a script
>> >
>> > ca=( "$@" )
>> >   checkarg() {
>>  !
>> > (( $# )) &&
>> > return 1
>> > local IFS=$'\xff \t\n' i a
>> > i=${IFS:0:1}
>> >  for a ; do
>> > [[ ${ca[*]//"$i"/'^^'} == @(#|"$i")@("$a")@(%|"$i") ]] ||
>> > return 1
>> >  done
>> > return 0
>> >   }
>>
>
the solution is
[[ $i$ca$i == $i$a$i ]]
i think
.. thanks and greets ..

> checkarg 1 &&
>> > exit
>>
>> This function should return 1 immediately if you give it any arguments.
>> The function you pasted into this email is not the same one you're
>> running.
>>
>
> gmail client stripped the ! sign away it seems to me
> i send full script
>
> > -- the script runs , but at checkarg 1 ( 1 is first and only arg to
>> script
>> > ) fails at the [[ , not returning 0
>> >
>> > -x says
>> >
>> > + ca=("$@")
>> > + checkarg 1
>> > + ((  1  ))
>> > + local 'IFS=�
>> > ' i a
>> > + i=$'\377'
>> > + for a in "$@"
>> > + [[ 1 == @(#|\�)@(\1)@(%|\�) ]]
>> > + return 1
>> >
>> > but why doesnt it return null ?
>>
>> Assuming that the function you executed actually has
>>
>>     (( $# )) || return 1
>>
>> instead of
>>
>>     (( $# )) && return 1
>>
>
> sorry just gmail version .. code goes ! (( ..
> btw at -x u'd see the [[ gets run
> eg it didnt return 1 on $?
>
> you are trying to match the string "1" against a pattern whose first
>> character must be "#" or $'\xff', and "1" is not either of these.  So
>> it doesn't match the pattern.
>>
>
> i thought in extglob there is # and %
> after thinking long i think i got the solution
> hmm nah i didnt get it
>
> What happens from there is anyone's guess, because you aren't showing
>> us the right function.
>>
>
> its actual code and -x from it
> just weird the ! sign went away
>
> > its supposed to do : ( argslist , with arg '1' as check )
>> > args list , flat , xff separator , with inside occurrence of xff
>> > ==
>> > @(either beginning of whole || or xff )
>>
>> Why do you believe that the "#" character is "beginning of whole"?
>> It's not.
>>
>> Glob patterns are always anchored, similar to a regex with ^ at the
>> start and $ at the end.  You don't need to put # in to serve as an
>> anchor.  If you put # there, it's just a plain, literal character
>> that has to be matched.
>>
>
> hmm hard to code an args check like this ..
>
> > is xff 377 ?
>>
>> \xff is \0377.  They are both encodings of a byte where every bit is 1.
>>
>>