Re: sed with Variable Substitution in the command

[alex xmb sw ratchev]

huuuu , yeah fail test

{13..1}
bash returns wrong 1 at end for $11
yes
uhhhhh ... how ' new ' or ' old ' is this

i was under the hard , wrong , delusion , that bash had done this
differently ..
while also i thought gawk was doing it wrong
but gawk says it got it right , $11 being 3

a=( {13..1} ) ; gawk <<<${a[*]} ' { print $11 } '

weird .. i might have suxxed that knowledge from long ago ...
hmm

greets ! ..


On Fri, Sep 27, 2024 at 10:07 AM Andreas Kähäri <andreas.kahari@abc.se>
wrote:

> On Fri, Sep 27, 2024 at 09:05:47AM +0200, alex xmb sw ratchev wrote:
> > u talk in bash , or posix mode ? or awk ?
> >
> > set {1..13}
> > echo $11
> > 11
>
> The output here, "11", is the value of the 1st positional parameter with
> an extra "1" appended to the end.
>
> Had you outputted the value of "${11}", you would also have gotten "11",
> because the value of the 11th positional parameter is "11" (because of
> the way you set the values of the positional parameters).
>
> A better test would have been to set the positional parameters to
> something other than their ordinal numbers:
>
>         set -- {a..m}
>
> Outputting "$11" would then have given you "a1", while outputting
> "${11}" would have given you "k".  Which of these is the "correct"
> output depends on what you are trying to do.
>
> >
> > bash
> >
> > On Thu, Sep 26, 2024 at 7:16 PM Greg Wooledge <greg@wooledge.org> wrote:
> > >
> > > On Thu, Sep 26, 2024 at 18:53:59 +0200, alex xmb sw ratchev wrote:
> > > > On Thursday, September 26, 2024, Wiley Young <wyeth2485@gmail.com>
> > wrote:
> > > > > "${1}"
> > > > >             "$1" is okay
> > > > > "${11}"
> > > > >             "$11" is an error
> > >
> > > > sorry .. where is $11 and error ?
> > >
> > > $11 would be equivalent to ${1}1 which is not what's intended.
>
> --
> Andreas (Kusalananda) Kähäri
> Uppsala, Sweden
>
> .
>
>