Re: case $var in $list) issue

[Greg Wooledge]

On Fri, Nov 01, 2024 at 20:07:10 +0100, #!microsuxx wrote:
> ~ $ x="${array[*]}"
> ~ $ echo $x
> zero one two three four

You're still failing to quote.  echo "$x" is needed to have even the
slightest *chance* of seeing the correct output.

printf '%s\n' "$x" would guarantee seeing the correct output.  But for
debugging purposes, echo "$x" may be good enough, often enough.

echo $x, however, will never be acceptable.