Re: nested groups?

[Mark . Burgess]

You are confusing groups and variables.
$(a) is a variable not a group

M

On 29 Mar, rader@ginseng.hep.wisc.edu wrote:
> 
>  groups:
>    a = ( x y )
>    b = ( z )
>    c = ( $(a) ${b} )
> 
> doesn't seem to define c as x y z (or as z).
> 
> anybody know of a workaround?  i'm using
> 
>  a = ( x y )
>  b = ( z )
>  groups: 
>    a = ( $(a) )
>    b = ( $(b) )
>    c = ( $(a) $(b) )
> 
> but that's kinda redundant and a bit ugly.
> 
> steve 
> - - - 
> systems & network guy
> high energy physics
> university of wisconsin
> 
> 
> 
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