Re: nested groups?

[Tim Nelson]

        So, if I understand, what he actually wants is:

groups:
        a = ( x y )
        b = ( z )
        c = ( a b )

        Right?

On Mon, 29 Mar 2004 Mark.Burgess@iu.hio.no wrote:

>
> You are confusing groups and variables.
> $(a) is a variable not a group
>
> M
>
> On 29 Mar, rader@ginseng.hep.wisc.edu wrote:
> >
> >  groups:
> >    a = ( x y )
> >    b = ( z )
> >    c = ( $(a) ${b} )
> >
> > doesn't seem to define c as x y z (or as z).
> >
> > anybody know of a workaround?  i'm using
> >
> >  a = ( x y )
> >  b = ( z )
> >  groups:
> >    a = ( $(a) )
> >    b = ( $(b) )
> >    c = ( $(a) $(b) )
> >
> > but that's kinda redundant and a bit ugly.
> >
> > steve
> > - - -
> > systems & network guy
> > high energy physics
> > university of wisconsin
> >
> >
> >
> > _______________________________________________
> > Help-cfengine mailing list
> > Help-cfengine@gnu.org
> > http://mail.gnu.org/mailman/listinfo/help-cfengine
>
>
>
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Tim Nelson
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