Re: nested groups?

[rader]

Excellent!  Works for me.  Thanks Tim.

steve 
- - - 
systems & network guy
high energy physics
university of wisconsin


 > ---- Original Message ----
 > From: Tim Nelson
 >      So, if I understand, what he actually wants is:
 > 
 > groups:
 >      a = ( x y )
 >      b = ( z )
 >      c = ( a b )
 > 
 >      Right?  

 > On Mon, 29 Mar 2004 Mark.Burgess@iu.hio.no wrote:
 > 
 > > 
 > > You are confusing groups and variables.
 > > $(a) is a variable not a group
 > > 
 > > M

 > > On 29 Mar, rader@ginseng.hep.wisc.edu wrote:
 > > > 
 > > >  groups:
 > > >    a = ( x y )
 > > >    b = ( z )
 > > >    c = ( $(a) ${b} )
 > > > 
 > > > doesn't seem to define c as x y z (or as z).
 > > > 
 > > > anybody know of a workaround?  i'm using
 > > > 
 > > >  a = ( x y )
 > > >  b = ( z )
 > > >  groups: 
 > > >    a = ( $(a) )
 > > >    b = ( $(b) )
 > > >    c = ( $(a) $(b) )
 > > > 
 > > > but that's kinda redundant and a bit ugly.
 > > > 
 > > > steve 
 > > > - - - 
 > > > systems & network guy
 > > > high energy physics
 > > > university of wisconsin