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Re: [Help-glpk] two fases
From: |
Andrew Makhorin |
Subject: |
Re: [Help-glpk] two fases |
Date: |
Thu, 26 Jan 2006 03:00:00 +0300 |
> I am working with the following problem :
>
> MAX Z=x1+6x2-7x3+x4+5x5
>
> Subjecto to
>
> 5x1-4x2+13x3-2x4+x5=20
> x1-x2+5x3-x4+x5=8
>
> the obtained result when I put the problem in GLPK is:
>
> PROBLEM HAS UNBOUNDED SOLUTION
This means that your instance has no finite maximum.
Maximize
Z:x1+6x2-7x3+x4+5x5
Subject to
e1:5x1-4x2+13x3-2x4+x5=20
e2:x1-x2+5x3-x4+x5=8
End
Problem:
Rows: 2
Columns: 5
Non-zeros: 10
Status: UNBOUNDED
Objective: Z = 28 (MAXimum)
No. Row name St Activity Lower bound Upper bound Marginal
------ ------------ -- ------------- ------------- ------------- -------------
1 e1 NS 20 20 = -1
2 e2 NS 8 8 = 6
No. Column name St Activity Lower bound Upper bound Marginal
------ ------------ -- ------------- ------------- ------------- -------------
1 x1 B 3 0
2 x2 NL 0 0 8
3 x3 NL 0 0 -24
4 x4 NL 0 0 5
5 x5 B 5 0
Karush-Kuhn-Tucker optimality conditions:
KKT.PE: max.abs.err. = 5.00e-16 on row 2
max.rel.err. = 1.92e-16 on row 2
High quality
KKT.PB: max.abs.err. = 0.00e+00 on row 0
max.rel.err. = 0.00e+00 on row 0
High quality
KKT.DE: max.abs.err. = 1.15e-14 on column 1
max.rel.err. = 3.20e-15 on column 1
High quality
KKT.DB: max.abs.err. = 2.60e+01 on column 2
max.rel.err. = 1.03e+00 on column 2
DUAL SOLUTION IS INFEASIBLE
Unbounded ray: column 2
End of output
A feasible basic solution found by glpsol is:
x1 = 3, x2 = 0, x3 = 0, x4 = 0, x5 = 5
However, variable x2 having positive reduced cost can infinitely
increase, that leads to infinitely increasing the objective function.
>
> That was necessary to work with the method of two phases. GLPK has
> the option to work with this method ?????
>
> That the ideal solution of the problem is : x3=12/7 x2=4/7 all
> other xj=0 z=-60/7 but I not as obtaining this response using GLPK.
>
> That I can do to obtain the ideal solution ?????????????
Can you explain what is ideal solution?