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Re: [Help-glpk] Linear expressions in the integrands of iteratedexpressi
From: |
Barry Rountree |
Subject: |
Re: [Help-glpk] Linear expressions in the integrands of iteratedexpressions |
Date: |
Sun, 22 Oct 2006 23:16:42 -0400 |
User-agent: |
KMail/1.9.1 |
On Sunday 22 October 2006 22:23, Tor Myklebust wrote:
> > That's a very good suggestion, but it doesn't quite handle
> > what I'm trying to do. I'm trying to code up
> > exclusivity without having to use "binary", e.g.
> >
> > s.t. foo:sum{i in I} x[i] = 42;
> > s.t. bar:max{i in I} x[i] = 42;
>
> The set of x that satisfy both constraints is not a convex set, so you are
> unlikely to have much luck representing these constraints in a linear
> program. (It is, in fact, a finite set if each x[i] is constrained to be
> nonnegative.)
Ah, didn't know that. Easy enough to get around, though, yes?
s.t. foo:sum{i in I} x[i] = 42 + slop;
s.t. bar:max{i in I} x[i] = 42 - slop;
Barry