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From: | D'Agostino, Larry - TX |
Subject: | [Help-glpk] GLPK shift coverage example |
Date: | Fri, 13 Mar 2009 17:03:14 -0500 |
I’ve been working on a workforce shift coverage model
recently. The purpose is to find an optimal shift schedule given various
shift schedule proposals. The example below is just one proposal. This
is a very common problem among assigning crew members to a given shift
allotment to cover demand. I think this type of problem makes for a great
example. Andrew, feel free to use this model as an example in GLPK (if
you feel it has not been used already). I’m sure your going to have
to modify the formatting as I copied it over from GUSEK. And as always I
would welcome critiques and (better yet) improvements. File: shiftcover.mod /* WORKFORCE SHIFT COVERAGE assignment problem */ /* Written by Larry D'Agostino <larrydag -at- sbcglobal
-dot- com> Maximize Productivity with
Industrial Engineer and Operations Research Tools
http://industrialengineertools.blogspot.com /* The WORKFORCE SHIFT COVERAGE is an assigment problem that
determines the schedule of crew given available time and
shifts. The objective is to cover the available time
given hourly demand with the minimum number of crew members. This is a set covering problem that is
very common among finding crew and shift allocations. */ /* ----- Model PARAMTERS and SETS -----*/ param numhrs; /* number of hours of operations in a given day */ param dys; /* number of days in a week */ set S; /* set of crew shifts */ set H := 1..numhrs; /* set of hours of a day*/ set D; /* set of days of a week*/ param dmnd{h in H, d in D}; /* demand for crew members given h hour and d day */ param shifts{d in D, h in H, s in S}; /* shifts to assign to crew members given d day, h hour, and
s shift schedule /*----- Model VARIABLES -----*/ var crew{s in S}, integer, >=0; /* number of crew assigned to shift S */ /*----- Model CONSTRAINTS -----*/ s.t. Coverage{h in H, d in D}: sum{s in S}
crew[s]*shifts[d,h,s] >= dmnd[h,d]; /* number of crew to cover with a shift given hourly
demand and day */ /*----- Model OBJECTIVE -----*/ minimize obj: sum{s in S} crew[s]; /* minimize number of crew to cover demand*/ solve; display crew; printf "\n"; printf "Total Crew: %3d\n\n", sum{s in S} crew[s]; printf "\n\n"; printf "Weekly Crew Schedule\n\n"; printf "Hour "; printf{d in D} " %s ", d; printf "\n"; for {h in H} { printf " %2s ",h; printf{d in D} " %3d ", sum{s
in S} crew[s]*shifts[d,h,s]; printf "\n"; } printf"\n"; data; param numhrs := 16; set D := SUN, MON, TUE, WED, THU, FRI, SAT; set S := Sh1, Sh2, Sh3, Sh4, Sh5, Sh6, Sh7, Sh8, Sh9; param dmnd : SUN
MON TUE WED
THU FRI SAT := 1
0 3
3 4
3 2 0 2
0 14 14
16 14
12 12 3
0 24 24
27 24
20 15 4
0 28 28
32 28
23 15 5
0 33 33
37 33
24 16 6
0 34 34
38 34
24 15 7
0 35 35
39 35
25 11 8 0
35 35
40 35
27 0 9
0 34 34
39 34
25 0 10
0 31 31
35 31
24 0 11
2 24 24
27 24
25 0 12 3
19 19
21 19
21 0 13
2 24 24
27 24
13 0 14
2 16 16
18 16
0 0 15
0 7
7 7
7 0 0 16
0 5
5 5
5 0 0; param shifts := ['SUN',*,*]:
Sh1 Sh2 Sh3 Sh4 Sh5 Sh6 Sh7 Sh8
Sh9 := 1
0 0 0 0
0 0 0 0
0 2
0 0 0 0
0 0 0 0
0 3
0 0 0 0
0 0 0 0
0 4
0 0 0 0
0 0 0 0
0 5
0 0 0 0
0 0 0 0
0 6
0 0 0 0
0 0 0 0
0 7
0 0 0 0
0 0 0 0
0 8
0 0 0 0
0 0 0 0
0 9
0 0 0 0
0 0 0 0
0 10
0 0 0 0
0 0 0 0
0 11 0
0 0 0 0
0 0 0 1 12
0 0 0 0
0 0 0 0
1 13
0 0 0 0
0 0 0 0
1 14
0 0 0 0
0 0 0 0
1 15
0 0 0 0
0 0 0 0
0 16
0 0 0 0
0 0 0 0
0 ['MON',*,*]:
Sh1 Sh2 Sh3 Sh4 Sh5 Sh6 Sh7 Sh8
Sh9 := 1
1 0 0 0
0 0 0 0
0 2
1 1 0 0
0 0 0 0
0 3
1 1 1 0
0 0 0 0
0 4
1 1 1 1
0 0 0 0
0 5
0 1 1 1
1 0 0 0 0 6
1 0 1 1
1 1 0 0
1 7
1 1 0 1
1 1 1 0
1 8
1 1 1 0
1 1 1 1
1 9
1 1 1 1
0 1 1 1
1 10 0
1 1 1 1
0 1 1 1 11
0 0 1 1
1 1 0 1
0 12
0 0 0 1
1 1 1 0
1 13
0 0 0 0
1 1 1 1
1 14
0
0 0 0 0
1 1 1 1 15
0 0 0 0
0 0 1 1
1 16
0 0 0 0
0 0 0 1
1 ['TUE',*,*]:
Sh1 Sh2 Sh3 Sh4 Sh5 Sh6 Sh7 Sh8
Sh9 := 1 1
0 0 0 0
0 0 0 0 2
1 1 0 0
0 0 0 0
0 3
1 1 1 0
0 0 0 0
0 4
1 1 1 1
0 0 0 0
0 5
0 1 1 1
1 0 0 0
0 6
1 0 1 1
1 1 0 0
1 7
1 1 0 1
1 1 1 0
1 8
1 1 1 0
1 1 1 1
1 9 1
1 1 1 0
1 1 1 1 10
0 1 1 1
1 0 1 1
1 11
0 0 1 1
1 1 0 1
0 12
0 0 0 1
1 1 1 0
1 13
0 0
0 0 1 1
1 1 1 14
0 0 0 0
0 1 1 1
1 15
0 0 0 0
0 0 1 1
1 16
0 0 0 0
0 0 0 1
1 ['WED',*,*]: Sh1
Sh2 Sh3 Sh4 Sh5 Sh6 Sh7 Sh8 Sh9 := 1
1 0 0 0
0 0 0 0
0 2
1 1 0 0
0 0 0 0
0 3
1 1 1 0
0 0 0 0
0 4
1 1
1 1 0 0
0 0 0 5
0 1 1 1
1 0 0 0
0 6
1 0 1 1
1 1 0 0
1 7
1 1 0 1
1 1 1 0
1 8
1 1 1 0
1 1 1 1
1 9
1 1 1 1
0 1 1 1
1 10
0 1 1 1
1 0 1 1
1 11
0 0 1 1
1 1 0 1
0 12
0 0 0 1
1 1 1 0
1 13
0 0 0 0
1 1 1 1
1 14
0 0 0 0
0 1 1 1
1 15
0 0 0 0
0 0 1 1
1 16 0
0 0 0 0
0 0 1 1 ['THU',*,*]:
Sh1 Sh2 Sh3 Sh4 Sh5 Sh6 Sh7 Sh8
Sh9 := 1
1 0 0 0
0 0 0 0
0 2
1 1 0 0
0 0 0 0
0 3
1 1 1 0
0 0 0 0
0 4
1 1 1 1
0 0 0 0
0 5
0 1 1 1
1 0 0 0
0 6
1 0 1 1
1 1 0 0
0 7 1
1 0 1 1
1 1 0 0 8
1 1 1 0
1 1 1 1
0 9
1 1 1 1
0 1 1 1
0 10
0 1 1 1
1 0 1 1
0 11
0 0
1 1 1 1
0 1 0 12
0 0 0 1
1 1 1 0
0 13
0 0 0 0
1 1 1 1
0 14
0 0 0 0
0 1 1 1
0 15
0 0 0 0
0 0 1 1
0 16
0 0 0 0
0 0 0 1
0 ['FRI',*,*]:
Sh1 Sh2 Sh3 Sh4 Sh5 Sh6 Sh7 Sh8
Sh9 := 1
1 0 0 0
0 0 0 0
0 2
1
1 0 0 0
0 0 0 0 3
1 1 1 0
0 0 0 0
0 4
1 1 1 1
0 0 0 0
0 5
0 1 1 1
1 0 0 0
0 6
1 0 1 1
1 1 0 0
0 7
1 1 0 1
1 1 1 0
0 8
1 1 1 0
1 1 1 1
0 9
1 1 1 1
0 1 1 1
0 10 0
1 1 1 1
0 1 1 0 11
0 0 1 1
1 1 0 1
0 12
0 0 0 1
1 1 1 0
0 13
0 0 0 0
1 1 1 1
0 14
0 0
0 0 0 1
1 1 0 15
0 0 0 0
0 0 1 1
0 16
0 0 0 0
0 0 0 1
0 ['SAT',*,*]:
Sh1 Sh2 Sh3 Sh4 Sh5 Sh6 Sh7 Sh8
Sh9 := 1 0
0 0 0 0
0 0 0 0 2
0 0 0 0
0 0 0 0
1 3
0 0 0 0
0 0 0 0
1 4
0 0 0 0
0 0 0 0
1 5
0 0
0 0 0 0
0 0 1 6
0 0 0 0
0 0 0 0
1 7
0 0 0 0
0 0 0 0
1 8
0 0 0 0
0 0 0 0
0 9
0 0 0 0
0 0 0 0
0 10
0 0 0 0
0 0 0 0
0 11
0 0 0 0
0 0 0 0
0 12
0 0 0 0
0 0 0 0
0 13
0 0 0 0
0 0 0 0
0 14
0 0 0 0
0 0 0 0
0 15
0 0 0 0
0 0 0 0
0 16
0 0 0 0
0 0 0 0
0; Larry http://industrialengineertools.blogspot.com |
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