Hi Manuel,
try setting StorageFlag to 1 or 0 as a parameter (based on your data), and then doing this:
subject to linctr14-1 {i in PeriodsCount: i == 1}:
StorageEnergy[i] >= StorageFlag*( existing constraint ) ;
subject to linctr14-0 {i in PeriodsCount: i == 1}:
StorageEnergy[i] <= StorageFlag*( existing constraint ) + (1-StorageFlag) * M ;
When StorageFlag = 1, these two constraints equate to your equality constraint.
When StorageFlag = 0, the constraints just become bounds (0 and M). If you want to allow StorageEnergy[i] to be negative, you could add " - (1-StorageFlag)*M" to the first constraint.
I *think* this will work -- good luck!
Best regards,
Greg
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Message: 1
Date: Tue, 24 Nov 2020 18:59:09 +0000
From: Manuel Castro <m.j.castro@zoho.com>
To: "help-glpk" <help-glpk@gnu.org>
Subject: Help: Switch constraints on or off
Message-ID: <175fb9fb6e3.12bae7aa873758.2962621200961588692@zoho.com" target="_blank">175fb9fb6e3.12bae7aa873758.2962621200961588692@zoho.com>
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Hi there,
I am wondering how I can use an if statement to turn a constraint on or off.
For example in my problem I have the following constraint:
subject to linctr14 {i in PeriodsCount: i == 1}: StorageEnergy[i] = (StorageStateCharge * StorageEnergyRating + ((StorageEfficiencyCharge * (StoragePowerCharge[i])) - ((StoragePowerDischarge[i]) / StorageEfficiencyDischarge)));
Now, I only want to consider storage in my problem if an object storage actually exists.
For that, I would have a StorageStatusFlag which if equal to "1" then I would consider the constraint in my problem.
For example:
If (StorageStatusFlag == 1) then
subject to linctr14 {i in PeriodsCount: i == 1}: StorageEnergy[i] = (StorageStateCharge * StorageEnergyRating + ((StorageEfficiencyCharge * (StoragePowerCharge[i])) - ((StoragePowerDischarge[i]) / StorageEfficiencyDischarge)));
end if
This is what I used to do in "mosel" language from FICO Xpress (I don't have a license anymore so I am discovering GLPK ). How can I do this in GLPK language? What's the workaround that we can use for this?
Many thanks in advance for your help. It's really appreciated.
Kind regards,
Manuel.