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Re: regex question
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From: |
Jesper Harder |
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Subject: |
Re: regex question |
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Date: |
Mon, 19 May 2003 18:18:49 +0200 |
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User-agent: |
Gnus/5.1003 (Gnus v5.10.3) Emacs/21.3.50 (gnu/linux) |
upro <upro@gmx.net> writes:
> I want to use M-x replace-regexp like this
>
> s/[a-z]''/$1"/g
I'm not sure what this means, but I assume you want to replace stuff
like a'' with a".
> the first part [a-z]'' works, but then the mathed lowercase letter is
> not reinserted, but a litteral $1.
>
> How does that work in emacs-regex? I don't find the relevant info in
> the info file...
You could do:
`M-x replace-regexp RET \([a-z]\)'' RET \1" RET'
Regexp syntax in Emacs is described in <info://emacs/Regexps>.